Optimal. Leaf size=235 \[ -\frac{50 \sqrt [4]{5} \left (231+26 \sqrt{5}\right ) \left (x^2+\sqrt{5}\right ) \sqrt{\frac{x^4+5}{\left (x^2+\sqrt{5}\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{x}{\sqrt [4]{5}}\right ),\frac{1}{2}\right )}{1001 \sqrt{x^4+5}}+\frac{1}{143} \left (33 x^2+26\right ) \left (x^4+5\right )^{3/2} x^5+\frac{10 \left (77 x^2+78\right ) \sqrt{x^4+5} x^5}{1001}+\frac{20}{13} \sqrt{x^4+5} x^3-\frac{300 \sqrt{x^4+5} x}{13 \left (x^2+\sqrt{5}\right )}+\frac{200}{77} \sqrt{x^4+5} x+\frac{300 \sqrt [4]{5} \left (x^2+\sqrt{5}\right ) \sqrt{\frac{x^4+5}{\left (x^2+\sqrt{5}\right )^2}} E\left (2 \tan ^{-1}\left (\frac{x}{\sqrt [4]{5}}\right )|\frac{1}{2}\right )}{13 \sqrt{x^4+5}} \]
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Rubi [A] time = 0.134444, antiderivative size = 235, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {1274, 1280, 1198, 220, 1196} \[ \frac{1}{143} \left (33 x^2+26\right ) \left (x^4+5\right )^{3/2} x^5+\frac{10 \left (77 x^2+78\right ) \sqrt{x^4+5} x^5}{1001}+\frac{20}{13} \sqrt{x^4+5} x^3-\frac{300 \sqrt{x^4+5} x}{13 \left (x^2+\sqrt{5}\right )}+\frac{200}{77} \sqrt{x^4+5} x-\frac{50 \sqrt [4]{5} \left (231+26 \sqrt{5}\right ) \left (x^2+\sqrt{5}\right ) \sqrt{\frac{x^4+5}{\left (x^2+\sqrt{5}\right )^2}} F\left (2 \tan ^{-1}\left (\frac{x}{\sqrt [4]{5}}\right )|\frac{1}{2}\right )}{1001 \sqrt{x^4+5}}+\frac{300 \sqrt [4]{5} \left (x^2+\sqrt{5}\right ) \sqrt{\frac{x^4+5}{\left (x^2+\sqrt{5}\right )^2}} E\left (2 \tan ^{-1}\left (\frac{x}{\sqrt [4]{5}}\right )|\frac{1}{2}\right )}{13 \sqrt{x^4+5}} \]
Antiderivative was successfully verified.
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Rule 1274
Rule 1280
Rule 1198
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int x^4 \left (2+3 x^2\right ) \left (5+x^4\right )^{3/2} \, dx &=\frac{1}{143} x^5 \left (26+33 x^2\right ) \left (5+x^4\right )^{3/2}+\frac{30}{143} \int x^4 \left (26+33 x^2\right ) \sqrt{5+x^4} \, dx\\ &=\frac{10 x^5 \left (78+77 x^2\right ) \sqrt{5+x^4}}{1001}+\frac{1}{143} x^5 \left (26+33 x^2\right ) \left (5+x^4\right )^{3/2}+\frac{100 \int \frac{x^4 \left (234+231 x^2\right )}{\sqrt{5+x^4}} \, dx}{3003}\\ &=\frac{20}{13} x^3 \sqrt{5+x^4}+\frac{10 x^5 \left (78+77 x^2\right ) \sqrt{5+x^4}}{1001}+\frac{1}{143} x^5 \left (26+33 x^2\right ) \left (5+x^4\right )^{3/2}-\frac{20 \int \frac{x^2 \left (3465-1170 x^2\right )}{\sqrt{5+x^4}} \, dx}{3003}\\ &=\frac{200}{77} x \sqrt{5+x^4}+\frac{20}{13} x^3 \sqrt{5+x^4}+\frac{10 x^5 \left (78+77 x^2\right ) \sqrt{5+x^4}}{1001}+\frac{1}{143} x^5 \left (26+33 x^2\right ) \left (5+x^4\right )^{3/2}+\frac{20 \int \frac{-5850-10395 x^2}{\sqrt{5+x^4}} \, dx}{9009}\\ &=\frac{200}{77} x \sqrt{5+x^4}+\frac{20}{13} x^3 \sqrt{5+x^4}+\frac{10 x^5 \left (78+77 x^2\right ) \sqrt{5+x^4}}{1001}+\frac{1}{143} x^5 \left (26+33 x^2\right ) \left (5+x^4\right )^{3/2}+\frac{1}{13} \left (300 \sqrt{5}\right ) \int \frac{1-\frac{x^2}{\sqrt{5}}}{\sqrt{5+x^4}} \, dx-\frac{\left (100 \left (130+231 \sqrt{5}\right )\right ) \int \frac{1}{\sqrt{5+x^4}} \, dx}{1001}\\ &=\frac{200}{77} x \sqrt{5+x^4}+\frac{20}{13} x^3 \sqrt{5+x^4}-\frac{300 x \sqrt{5+x^4}}{13 \left (\sqrt{5}+x^2\right )}+\frac{10 x^5 \left (78+77 x^2\right ) \sqrt{5+x^4}}{1001}+\frac{1}{143} x^5 \left (26+33 x^2\right ) \left (5+x^4\right )^{3/2}+\frac{300 \sqrt [4]{5} \left (\sqrt{5}+x^2\right ) \sqrt{\frac{5+x^4}{\left (\sqrt{5}+x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{x}{\sqrt [4]{5}}\right )|\frac{1}{2}\right )}{13 \sqrt{5+x^4}}-\frac{50 \sqrt [4]{5} \left (231+26 \sqrt{5}\right ) \left (\sqrt{5}+x^2\right ) \sqrt{\frac{5+x^4}{\left (\sqrt{5}+x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{x}{\sqrt [4]{5}}\right )|\frac{1}{2}\right )}{1001 \sqrt{5+x^4}}\\ \end{align*}
Mathematica [C] time = 0.0458187, size = 74, normalized size = 0.31 \[ \frac{1}{143} x \left (-650 \sqrt{5} \, _2F_1\left (-\frac{3}{2},\frac{1}{4};\frac{5}{4};-\frac{x^4}{5}\right )-825 \sqrt{5} x^2 \, _2F_1\left (-\frac{3}{2},\frac{3}{4};\frac{7}{4};-\frac{x^4}{5}\right )+\left (33 x^2+26\right ) \left (x^4+5\right )^{5/2}\right ) \]
Antiderivative was successfully verified.
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Maple [C] time = 0.023, size = 216, normalized size = 0.9 \begin{align*}{\frac{3\,{x}^{11}}{13}\sqrt{{x}^{4}+5}}+{\frac{25\,{x}^{7}}{13}\sqrt{{x}^{4}+5}}+{\frac{20\,{x}^{3}}{13}\sqrt{{x}^{4}+5}}-{\frac{{\frac{60\,i}{13}}}{\sqrt{i\sqrt{5}}}\sqrt{25-5\,i\sqrt{5}{x}^{2}}\sqrt{25+5\,i\sqrt{5}{x}^{2}} \left ({\it EllipticF} \left ({\frac{x\sqrt{5}\sqrt{i\sqrt{5}}}{5}},i \right ) -{\it EllipticE} \left ({\frac{x\sqrt{5}\sqrt{i\sqrt{5}}}{5}},i \right ) \right ){\frac{1}{\sqrt{{x}^{4}+5}}}}+{\frac{2\,{x}^{9}}{11}\sqrt{{x}^{4}+5}}+{\frac{130\,{x}^{5}}{77}\sqrt{{x}^{4}+5}}+{\frac{200\,x}{77}\sqrt{{x}^{4}+5}}-{\frac{40\,\sqrt{5}}{77\,\sqrt{i\sqrt{5}}}\sqrt{25-5\,i\sqrt{5}{x}^{2}}\sqrt{25+5\,i\sqrt{5}{x}^{2}}{\it EllipticF} \left ({\frac{x\sqrt{5}\sqrt{i\sqrt{5}}}{5}},i \right ){\frac{1}{\sqrt{{x}^{4}+5}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (x^{4} + 5\right )}^{\frac{3}{2}}{\left (3 \, x^{2} + 2\right )} x^{4}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (3 \, x^{10} + 2 \, x^{8} + 15 \, x^{6} + 10 \, x^{4}\right )} \sqrt{x^{4} + 5}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 4.01917, size = 160, normalized size = 0.68 \begin{align*} \frac{3 \sqrt{5} x^{11} \Gamma \left (\frac{11}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{11}{4} \\ \frac{15}{4} \end{matrix}\middle |{\frac{x^{4} e^{i \pi }}{5}} \right )}}{4 \Gamma \left (\frac{15}{4}\right )} + \frac{\sqrt{5} x^{9} \Gamma \left (\frac{9}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{9}{4} \\ \frac{13}{4} \end{matrix}\middle |{\frac{x^{4} e^{i \pi }}{5}} \right )}}{2 \Gamma \left (\frac{13}{4}\right )} + \frac{15 \sqrt{5} x^{7} \Gamma \left (\frac{7}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{7}{4} \\ \frac{11}{4} \end{matrix}\middle |{\frac{x^{4} e^{i \pi }}{5}} \right )}}{4 \Gamma \left (\frac{11}{4}\right )} + \frac{5 \sqrt{5} x^{5} \Gamma \left (\frac{5}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{5}{4} \\ \frac{9}{4} \end{matrix}\middle |{\frac{x^{4} e^{i \pi }}{5}} \right )}}{2 \Gamma \left (\frac{9}{4}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (x^{4} + 5\right )}^{\frac{3}{2}}{\left (3 \, x^{2} + 2\right )} x^{4}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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